01 - Speciation calculation

This example corresponds to the “Example 1-Speciation Calculation” from the Phreeqc manual. It can be retrieved from the Phreeqc Website.

This example calculates the distribution of aqueous species in seawater and the saturation state of seawater relative to a set of minerals.

Studies

This project contains 1 Studies.

  • PhreeqcStudy: “PhreeqcStudy”

Note that in this study new species and phases are added in the database

Db used: “Phreeqc_dat” database

TITLE Example 1.--Add uranium and speciate seawater.
SOLUTION 1  SEAWATER FROM NORDSTROM AND OTHERS (1979)
        units   ppm
        pH      8.22
        pe      8.451
        density 1.023
        temp    25.0
        redox   O(0)/O(-2)
        Ca              412.3
        Mg              1291.8
        Na              10768.0
        K               399.1
        Fe              0.002
        Mn              0.0002  pe
        Si              4.28
        Cl              19353.0
        Alkalinity      141.682 as HCO3
        S(6)            2712.0
        N(5)            0.29    gfw   62.0
        N(-3)           0.03    as    NH4
        U               3.3     ppb   N(5)/N(-3)
        O(0)            1.0     O2(g) -0.7
SOLUTION_MASTER_SPECIES
        U       U+4     0.0     238.0290     238.0290
        U(4)    U+4     0.0     238.0290
        U(5)    UO2+    0.0     238.0290
        U(6)    UO2+2   0.0     238.0290
SOLUTION_SPECIES
        #primary master species for U
        #is also secondary master species for U(4)
        U+4 = U+4
                log_k          0.0
        U+4 + 4 H2O = U(OH)4 + 4 H+
                log_k          -8.538
                delta_h        24.760 kcal
        U+4 + 5 H2O = U(OH)5- + 5 H+
                log_k          -13.147
                delta_h        27.580 kcal
        #secondary master species for U(5)
        U+4 + 2 H2O = UO2+ + 4 H+ + e-
                log_k          -6.432
                delta_h        31.130 kcal
        #secondary master species for U(6)
        U+4 + 2 H2O = UO2+2 + 4 H+ + 2 e-
                log_k          -9.217
                delta_h        34.430 kcal
        UO2+2 + H2O = UO2OH+ + H+
                log_k          -5.782
                delta_h        11.015 kcal
        2UO2+2 + 2H2O = (UO2)2(OH)2+2 + 2H+
                log_k          -5.626
                delta_h        -36.04 kcal
        3UO2+2 + 5H2O = (UO2)3(OH)5+ + 5H+
                log_k          -15.641
                delta_h        -44.27 kcal
        UO2+2 + CO3-2 = UO2CO3
                log_k          10.064
                delta_h        0.84 kcal
        UO2+2 + 2CO3-2 = UO2(CO3)2-2
                log_k          16.977
                delta_h        3.48 kcal
        UO2+2 + 3CO3-2 = UO2(CO3)3-4
                log_k          21.397
                delta_h        -8.78 kcal
PHASES
        Uraninite
        UO2 + 4 H+ = U+4 + 2 H2O
        log_k          -3.490
        delta_h        -18.630 kcal
END

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